Count by Group
【Question】
I have a text file with content like this and having 792 lines:
der 17788648
und 14355959
die 10939606
Die 10480597
Now I want to compare if "Die" and "die" are equal in lowercase. So if two strings in lowercase are equal, copy the word into a new text file in lowercase and sum the values.
Expected output:
der 17788648
und 14355959
die 21420203
I have this so far:
try {
BufferedReader bk = null;
BufferedWriter bw = null;
bk = new BufferedReader(new FileReader("outagain.txt"));
bw = new BufferedWriter(new FileWriter("outagain5.txt"));
List<String> list = new ArrayList<>();
String s = "";
while (s != null) {
s = bk.readLine();
list.add(s);
}
for (int k = 0; k < 793; k++) {
String u = bk.readLine();
if (list.contains(u.toLowerCase())) {
//sum values?
} else {
bw.write(u + "\n");
}
}
System.out.println(list.size());
} catch (Exception e) {
System.out.println("Exception caught :" + e);
}
【Answer】
This is basic grouping and aggregation operation. As Java lacks a universal structured computation class library, the hardcoding is roundabout. Here we handle it in SPL (Structured Process Language):
A |
|
1 |
=file("d:\\data.txt").import(;," ").groups(lower(#1);sum(#2)) |
2 |
=file("d:\\result.txt").export(A1; " ") |
A1: Group the txt file by lowercase in the first field and then sum the second field.
A2: Use this statement if you want to write the result to a target file.
To integrate an SPL script with a Java application, refer to How to Call an SPL Script in Java.
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